πΏ^(β1) (1/(π β3)^5 +2/((π +1)^2+4))
TAM3B - Differential equations
( x - y ) dx -( x + y ) dy =0 Exact Equation If the first order partial derivatives of M( x,y ) and N( x,y ) are continuous then M dx + N dy = 0 is an exact equation if and only if β M/ β y = β N/β x Hence to solve the exact equation M dx + N dy = 0 Integrate M with respect to x keeping y constant Integrate those terms in N not containing x with respect to y The sum of those two integrals equated to c is the solution. EXAMPLE 1 ( x^2-2xy+3y^2 )dx+(y^2+6xy-x^2 )dy=0 EXAMPLE 2 ( 2xy-sec^2β‘x )dx+(x^2+2y)dy=0 EXAMPLE 3 Find the value of β n β for which ( x+ye^2xy )dx+nxe^2xy dy=0 and solve it EXAMPLE 4 ( sinβ‘ x. tanβ‘ y+1)dx-(cosβ‘x.sec^2β‘y )dy=0 EXAMPLE 5 ( e^y+1) cosβ‘ x dx+e^y sinβ‘x dy=0
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